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View Full Version : Max mechanical power of motors, how is it useful?


Ken Leung
09-11-2001, 10:20
I understand that the maximum mechanical power output by a DC motor can be obtain from the equation:

Pmax = 1/4 * Torque max. * w max. (Angular velocity)

Now, my question is, what is so important about this equation? Is it only used to calculate available power from motors, or can it be used in some other way?

I remember that while controlling the motors, we should always set the mechanical power output of motor a little less than the Pmax... Well, how exactly do we do that?

Do we use the value of power reflected after setting up the gearing, or in another words, do we figure out the the mechanical power after we attach the gears and arms? If so, do this mean that we should use gear ratio to control the mechanical power and aim to design a ratio to achieve a P close to Pmax?

Should we only include the gears when calculating power output, or should we also include the components we use (such as wheel, or arms)?

Joe Johnson
09-11-2001, 14:15
Power is the thing that you should be thinking about when you choose a motor for a particular job.

Given that you want to lift an arm and ball of weight X a distance Y in time T, you know how much power you are requiring.

If your motor cannot provide that much power you have to choose another or relax your requirements.

Once you know what motor, then you can pick your gear ratio such that your expected load reflected back to the motor gives you a torque between 20-50% of your stall torque of the motor.

If you do this, your motor will be happy, your robot will be happy, and your fans will be happy.

This is obviously a much condensed answer, but the basic idea is sound.

Joe J.