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Ether
10-09-2013, 12:51
How many proper subsets are there of a set containing 30,000 elements?

Camren
10-09-2013, 17:12
(2^n)-n
(2^30,000)-30,000
(7.951x10^9030)-30000
7.851x10^9026

Ether
10-09-2013, 17:21
(2^n)-n

Almost, but not quite right.


(7.951x10^9030)-30000
7.851x10^9026

If you subtract a mere 30000 from 10^9030 you don't get 10^9026

Ether
11-09-2013, 23:02
If anybody's still interested here's the solution:

The number of proper subsets of a set containing N elements is 2N -1.

For N=30000, the number of proper subsets is 230000 -1.

The "-1" totally insignificant for such a large N.

Find "x" such that 10x = 230000...

take log10 of both sides:

log10(10x) = log10(230000) ..∴.. x = 30000*log10(2) = 9030.9

109030.9 = 100.9 * 109030 = 7.94E9030

Nate Laverdure
12-09-2013, 07:17
-1 is because the complete set (with all N elements) is not counted? A set cannot be a proper subset of itself?

The empty set is still counted, correct?

Ether
12-09-2013, 09:23
-1 is because the complete set (with all N elements) is not counted?

Correct.


A set cannot be a proper subset of itself?

Correct.


The empty set is still counted, correct?

Correct.