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How many proper subsets are there of a set containing 30,000 elements?
(2^n)-n
(2^30,000)-30,000
(7.951x10^9030)-30000
7.851x10^9026
(2^n)-n
Almost, but not quite right.
(7.951x10^9030)-30000
7.851x10^9026
If you subtract a mere 30000 from 10^9030 you don't get 10^9026
If anybody's still interested here's the solution:
The number of proper subsets of a set containing N elements is 2N -1.
For N=30000, the number of proper subsets is 230000 -1.
The "-1" totally insignificant for such a large N.
Find "x" such that 10x = 230000...
take log10 of both sides:
log10(10x) = log10(230000) ..∴.. x = 30000*log10(2) = 9030.9
109030.9 = 100.9 * 109030 = 7.94E9030
Nate Laverdure
12-09-2013, 07:17
-1 is because the complete set (with all N elements) is not counted? A set cannot be a proper subset of itself?
The empty set is still counted, correct?
-1 is because the complete set (with all N elements) is not counted?
Correct.
A set cannot be a proper subset of itself?
Correct.
The empty set is still counted, correct?
Correct.
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