Maximum Score

[Aignam]

Has anyone figured out the maximum score that an alliance can score in a single match?

Sorry if this question has already been presented. I searched the term 'maximum score' and found nothing relevant.

[HolyMasamune]

the highest plausible score a team could get is 410, with 10x5 balls and 2x10 balls with a 2x multiplier in the mobile goal, 13x5 balls, 2x10 balls (stolen from the other team), and a 2x multiplier in the stationary goal and then 2 robots hanging on the bar at the end

that is unless some team can manage to balance the 2x ball on one pvc :)

[Damian Manda]

The maximum score is dependant on the number of balls that can fit in the movable and stationary goals. If you figure that out, use a scoring program like this (http://www.chiefdelphi.com/forums/showthread.php?t=23554) to figure the max score out. Also, there is a difference between the max score that is possible for one team, and winning while getting the maximum ranking points (losers score). In that case, it would be:
(maxscore / 2) + 10 for your score and
(maxscore / 2) - 5 for their score
If I am thinking correctly, with you having a 2x multiplier for the one ball difference and them not.

--Damian Manda

[Jake Lewis]

what if you could put two 2X balls on top of a goal?? would that multiply by four? it is possible to do...since the pvc bends, you could get one ball into the goal and balance another on top...

[matt111]

well i assume u dont mean ur QPs which would be ur oppenents score. if u win that is all the matters

[Aignam]

what if you could put two 2X balls on top of a goal?? would that multiply by four? it is possible to do...since the pvc bends, you could get one ball into the goal and balance another on top...
Let's avoid this particular discussion here.

[kevin.li.rit]

560 If you can fit an infinite amount of balls into your two goals. If you score 2, 10pt balls. And 12 starting human player balls right?

[KenWittlief]

theres 18*5 in the ball release = 90
theres 6 starter balls per side * 5 = 30
theres 2 release balls per side * 10 = 20

thats 140 in small balls

double them all, that 280

hang both bots, that 380 points for 'your side' of the field

assuming you want you opponent to score high and leave them alone

if not, you cant get all 52 small balls in play into your two goals (the two goals can hold approx 35 balls) - so the absolute max score depends on that limtation.

[kevin.li.rit]

The 10 ball doesn't get doubled?

[KevinB]

the highest plausible score a team could get is 410, with 10x5 balls and 2x10 balls with a 2x multiplier in the mobile goal, 13x5 balls, 2x10 balls (stolen from the other team), and a 2x multiplier in the stationary goal and then 2 robots hanging on the bar at the end

that is unless some team can manage to balance the 2x ball on one pvc :)

12 balls will fit in a mobile goal?!

[KenWittlief]

The 10 ball doesn't get doubled?
sure it does!

[KenWittlief]

12 balls will fit in a mobile goal?!

the mobile goal will hold around 12 or 13

the big one, 23 to 25 (rough estimate without trying it yet)

[IMDWalrus]

The 10 ball doesn't get doubled?
Why wouldn't it?

[Thulium]

It seems as though most of you are missing something. You want to win to advance and the points you get are the losers. So you would need to figure not the max amount of points you can accumulate during a match, but the max amount of points you can get to beat your opponent by only 20 points assuming all balls are scored and multiplied and all robots are hanging.

This would work out as:
Your alliance - (19 x 5 + 20(bonus balls)) x 2(multiplier) + 2 hanging = 330 pts
Their alliance - (17 x 5 + 20(bonus balls)) x 2(multiplier) + 2 hanging = 310 pts
your max points = 310 pts and the win of course

[kevin.li.rit]

sure it does!

theres 18*5 in the ball release = 90
theres 6 starter balls per side * 5 = 30
theres 2 release balls per side * 10 = 20

thats 140 in small balls

double them all, that 280

hang both bots, that 380 points for 'your side' of the field

assuming you want you opponent to score high and leave them alone

if not, you cant get all 52 small balls in play into your two goals (the two goals can hold approx 35 balls) - so the absolute max score depends on that limtation.

Yes, well I wasn't sure since you didn't double the 2, 10pt balls in your totals.

[kevin.li.rit]

Knocking only one ball will trigger the release I assume?

[Dan Richardson]

The answer to your question.. tho it might not be possible is the highest score is 660pts

w/ 2 multipliers all balls and 2 bots hanging

technically tho.. w/ the 2 opponent bots hanging they can get 100 pts

however as we all know getting this many points would be useless except in finals

[KenWittlief]

Thulium - you forgot the 6 'starting balls' behind the wall on each end of the field - see drawings in section 4.1

Coffeism: I include 2 release balls in the 140 points count

and double all the 'small balls' is 280 - small size, not small value.

top score possible using only whats on your side of the field = 380 points

making it to the elimination rounds: Priceless!

[kevin.li.rit]

My mistake.

[KenWittlief]

Knocking only one ball will trigger the release I assume?


yes, either one - but if your opponent puts a release ball back onto your tee, then all the balls on the field jump back up into the ball release bin

(not really :c)

[Joe Ross]

It seems as though most of you are missing something. You want to win to advance and the points you get are the losers. So you would need to figure not the max amount of points you can accumulate during a match, but the max amount of points you can get to beat your opponent by only 20 points assuming all balls are scored and multiplied and all robots are hanging.

This would work out as:
Your alliance - (19 x 5 + 20(bonus balls)) x 2(multiplier) + 2 hanging = 330 pts
Their alliance - (17 x 5 + 20(bonus balls)) x 2(multiplier) + 2 hanging = 310 pts
your max points = 310 pts and the win of course

I get a different result, taking into account that there are the HP balls that you didn't account for and there and 3 multiplier balls:

Your alliance - (13 * 5 + 20(bonus balls)) * 4(multiplier) + 2 hanging = 440
Their alliance - (29 * 5 + 20(bonus balls)) * 2(multiplier) + 2 hanging = 430
your max points = 430 pts and the win of course

[piotrm]

I'm not sure if there is a maximum number of penalties or not, but would it not be possible for a team to continously goaltend and give the opposing team 10 or 20 points? Then do it again with the same ball ?

This would mean there is no maximum score (or minimum score). But I think first might DQ for too many penalties.

[kevin.li.rit]

I'm not sure if there is a maximum number of penalties or not, but would it not be possible for a team to continously goaltend and give the opposing team 10 or 20 points? Then do it again with the same ball ?

This would mean there is no maximum score (or minimum score). But I think first might DQ for too many penalties.

I think they would DQ, which is why I think that no team will build a robot that can goal tend, they'll either be useless or be disqualified when they try to goal tend.

[tkwetzel]

I have seen many inaccurate scores posted here. First of all, you need to assume a few things:
1) There are no goaltending penalties
2) There are no de-scoring penalties

If you did not assume those two things, your score could keep escalating until you ran out of time. However, assuming those two circumstances, you can score 380 while having your opponent score 375. If anyone would like this written out, let me know and I will show you how this is done.

[KenWittlief]

4.4.3 <G20>.. if a robot goaltends or descores any small ball, the referee will throw a green penalty flag and the opponents final score will be increased by twice the value of that small ball.

so if you block a 5 point shot, or knock a 5 point ball out of your opponents goal, they will get 10 points added after the match is over, for each offense.

I consider having your opponets score raised to be a penalty (for your team) you lost 10 or 20 points relative to their score.

[WakeZero]

I get a different result, taking into account that there are the HP balls that you didn't account for and there and 3 multiplier balls:

Your alliance - (13 * 5 + 20(bonus balls)) * 4(multiplier) + 2 hanging = 440
Their alliance - (29 * 5 + 20(bonus balls)) * 2(multiplier) + 2 hanging = 430
your max points = 430 pts and the win of course

I am getting this (I assume you can not get a 4x multiplier):

Winner: [(25 * 5) + (2 * 10)] * 2 + (2 * 50) = 390
Loser: [(23 * 5) + (2 * 10)] * 2 + (2 * 50) = 370

Remember, there are 6 HP balls on EACH side. Also, keep in mind that this score may not PHYSICALLY be possible if all of those balls don't fit into one goal ;)

[tkwetzel]

"I am getting this (I assume you can not get a 4x multiplier):

Winner: [(25 * 5) + (2 * 10)] * 2 + (2 * 50) = 390
Loser: [(23 * 5) + (2 * 10)] * 2 + (2 * 50) = 370"

That is not correct. You could only have 24 5 point balls, making your score 380. Your opponent would have 24 small balls, however, you would have to put one of them in an uncapped goal. This would give that team 375 points. Because of the numbers of balls that can fit in a goal, I would put all 4 of the 10 points balls in the opponents capped goal, because 25 will not fit in the goal and still allow a cap to be placed on it. Moving the other 2 10 point balls to the opponents goal, would allow you to remove 4 of their 5 point balls to be placed in one of your two goals which would both be capped. And for people asking, you are not allowed to have more than a 2X multiplyer.

[KenWittlief]

what are you talking about?! you can get all 52 small balls on the field into ONE stationary goal

IF you (ummmmmm) adjust them before you throw them

but you will need one STRONG human player to make the necessary adjustments :^)

[tkwetzel]

Adjustments to those balls would most likely be considered destruction of the field. So you would still have a limit on the number on which will go into the goals.

[WakeZero]

"I am getting this (I assume you can not get a 4x multiplier):

Winner: [(25 * 5) + (2 * 10)] * 2 + (2 * 50) = 390
Loser: [(23 * 5) + (2 * 10)] * 2 + (2 * 50) = 370"

That is not correct. You could only have 24 5 point balls, making your score 380. Your opponent would have 24 small balls, however, you would have to put one of them in an uncapped goal. This would give that team 375 points. Because of the numbers of balls that can fit in a goal, I would put all 4 of the 10 points balls in the opponents capped goal, because 25 will not fit in the goal and still allow a cap to be placed on it. Moving the other 2 10 point balls to the opponents goal, would allow you to remove 4 of their 5 point balls to be placed in one of your two goals which would both be capped. And for people asking, you are not allowed to have more than a 2X multiplyer.

You are correct, by 5 points. The uncapped ball is a good idea :yikes:

[KenWittlief]

how many balls must a goal hold down
before they call you The Man!
?

rough estimate is the stationary goal will hold around 23 small balls, leaving room to be capped

however, when the goal is almost full, it will be difficult to toss more into it

anyone place any wagers yet? Im willing to bet no team will ever get 26 balls in the stationary goal - capped or otherwise

I believe the max score in this game will not be acheived.

[tkwetzel]

you do not need to fit 26 balls into a goal to obtain the highest possible score. However, I also believe that the highest score will not be achieved.

[cbudrecki]

...you can score 380 while having your opponent score 375.

That's what I got:

Highest WINNING score is 380/375.
One team having 24 purple balls, 2 small yellow balls, and 1 large ball. (assuming all could fit in one goal, otherwise divide up with a large ball on the 2nd goal as well.) AND both bots hanging.
The other team having (goal 1) 23 purple, 2 small yellow, 1 large;(goal 2)one purple; AND again, both robots hanging.

Highest TYING score: 380/380
BOTH teams having 24 purple balls, 2 small yellow balls, and 1 large ball. AND both bots hanging.

Highest Possible: (assuming goals can hold 26 balls ea. + 1 large) : 660

[Wetzel]

The higest score is limited by time, not by the available balls.

If one team from each alliance can remove balls from the goal and feed it to the human player, who then rescores that ball, it gives the other team 10 points, or 20 points if you do it with the 10point ball. If both alliances do this for the length of the match, the score is only limited by the amount of time you spend doing it.


Wetzel
~~~~~~~~~
Hows that for a mindbender.

[Greg Powers]

Well if you start counting additional points from green flag penalties (credit for points of balls your opponent purposely blocks) then you cant really put a finite number on it.
The human player could just keep on getting the balls, throwing them, having them blocked, retrieving them, throwing them again, and getting them blocked, for the whole match.
It would rely on how many times they could re-collect the purple balls and throw them in 2 minutes. And there is no way of predicting how much that would be

sorry for the semi- "double" post
great minds think alike right?

[tkwetzel]

I had already mentioned earlier in the post that you had to assume two things to attain the highest point value:
1) No robot de-scored any balls (which is against the rules)
2) No robot goaltends (which is also against the rules)

[Jake Lewis]

had anyone figured out how many balls can fit into the stationary and mobile goals yet?

[that1guy]

the mobile goal will hold around 12 or 13

the big one, 23 to 25 (rough estimate without trying it yet)
hey thanks, that really helps to know :D