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Gearbox Calculations
Hey, I am having a hard time determining output speed and torque from the CIM-U-LATOR gearbox using the 2 RS-550 banebots motors. Can anyone explain what formulas I need to determine this? All help is appreciated.
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Re: Gearbox Calculations
First step is to count teeth.
I haven't used or seen a Cim-u-lator, but looking at the Banebots website it states that it has a 2.7:1 gear reduction. With a 10 tooth pinion on the motors driving a 27 tooth gear on the output shaft. If the tooth counts match what the website says then you can use the following formula to determine the output speed. Ratio=# Teeth in Gear/# Teeth in Pinion Output Shaft Speed=Motor Speed/Ratio Output Torque=Motor Torque*Ratio*(Number of Motors) Single Reduction gearboxes spur gearboxes are relatively efficient so you can probably neglect any losses from the gears in your calculations. It is probably worth stating that the motor speed is very dependent on load and so I typically suggest using a timing light to actually measure output speed. The formulas will usually get you in the ball park. |
Re: Gearbox Calculations
Quote:
Banebots 550-12: 19,300 rpm free speed 70.5 ozin stall torque 85 stall amps CIM-U-LATOR: Gear reduction is 2.7:1 ... so 2 550's on a CIM-U-LATOR would be free speed = 19,300/2.7 = 7148 rpm* stall torque = 2*70.5*2.7 = 381 ozin* stall amps = 2*85 = 170 amps Is that what you were asking? * neglecting gearbox efficiency losses |
Re: Gearbox Calculations
Yes, thanks for the help
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Re: Gearbox Calculations
Quote:
You can enter those numbers: stall torque = 2*70.5*2.7 = 381 ozin* free speed = 19,300/2.7 = 7148 rpm* stall amps = 2*85 = 170 amps free amps = 2.8 amps ... into the motor calculator using option "u" (UserDefined motor): Code:
Motor Calculator build MCALC32ae 2/21/2012 117am |
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