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Programming Puzzle
So I am trying to solve a programming problem that we are having with our T-Shirt cannon.
We have an analog rotation sensor that, as the cannon rotates a full rotation, the analog signal changes between 0 and 5V (linearly). My question is how I should deal with the transition between 0 to 5 volts in code. I want to be able to index the cannon so that it will snap to a position every 1/6th of the rotation. How should I do this? |
Re: Programming Puzzle
1) Measure how much rotation (in degrees) you get from 0 - 5 V of your sensor. Specifically, at 0 V, set the protractor to 0 degrees. Turn your cannon to the 5V reading and read the angle on the protractor.
2) Calculate the conversion factor from voltage to degrees. Let's say in step 1 you determined that at 5 volts the angle was 270 degrees. Then your conversion factor is 270 degrees / 5 V = 54 degrees/V 3) Now in LabVIEW, multiply your sensor reading (0 - 5V) by the conversion factor calculated in step 2. This will tell your code the angle of your cannon in degrees. 4) Use a PID loop to command your motor to any angle (in degrees) you want your cannon to shoot. |
Re: Programming Puzzle
But the problem is that I want the motor to rotate seamlessly through the 5v to 0v. For instance, if it overshoots a setpoint at 4.9 to .1, i don't want it to rotate the rest of the way around, but back up past 5v to 4.9
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BTW, how much of a deadband is there ? You may need to swap out your sensor. |
Re: Programming Puzzle
I think you misunderstand. If I was just using a simple comparator like > or < between setpoint and the analog input, and the cannon overshot past the wraparound, how do i force the cannon to go backwards instead of continuing another complete rotation to get back to the setpoint?
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Can you work from there, or do you need a more detailed explanation? Again, how large is the sensor's dead zone? You may need a new sensor. |
Re: Programming Puzzle
This zero crossing makes sense in theory but I am still unsure about how to implement it.
The dead zone is very small |
Re: Programming Puzzle
It may be easier to think in terms of "difference between where I am and where I want to be", and write as much of your code in that reference as possible. Then you will only have to handle the wrap-around in the one spot where you calculate that value. You will need some if statements and a little bit of math - if it is calculated as past half way around in one direction, map it in the other direction.
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Re: Programming Puzzle
I think I found a fix, I found a zero crossing VI that I am going to try and use. Lets see how it works
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Re: Programming Puzzle
I don't have LabVIEW here, so I can't say for sure, but I seem to recall that the LabVIEW PID VI has an input where you can tell it that your sensor wraps around, and the VI will handle it for you. Can someone confirm? |
Re: Programming Puzzle
I was not able to find that, but maybe i'm missing it.
I have drafted up some code that can (using the pt by pt zero crossing vi) count the number and direction of zero crossings and then calculate an integer for the number of full rotations. After that point, it simply multiplies that number by 5 and adds that to the number that it is receiving from the sensor. From that, I added PID functionality to control the spinning of the motor. We will see how it works tomorrow |
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You may want to look into a absolute position encoder if your pot just doesn't work out. |
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Then for your PID inputs, use: setpoint = desired canon angle in degrees processVariable = setpoint - corrected_angle_error |
Re: Programming Puzzle
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Bummer, because it'd be nice... Quote:
edit: here's a VI I quickly wrote up that demonstrates both of the methods Ether wrote up: Attachment 12945 |
Re: Programming Puzzle
You could also try using a PID to minimize error, rather than reach a setpoint.
IE: Rather than My setpoint is currently 4.5 my process variable is at .1 Say My setpoint is always 0, currently my process variable is -.6 (where -.6 is the circular difference between your 'goal' and your 'actual') then when your goal changes, the frame of reference you use to calculate your process variable changes, and your (probably only proportional gain?) controller will move your motor. |
Re: Programming Puzzle
I wrote a vi called HeadingWrap.vi that we've used for autonomous. You can use it to convert an angle outside of +/-180 degrees to be within the +/-180 degree range. You can use it to do what you're trying to do.
This is how it's used: Calculate your angle error into your PID (i.e. desired - actual) and feed the result into HeadingWrap.vi. The output will come out within the +/-180 range and will give you the shortest turn to your desired angle. You can find it here: http://www.chiefdelphi.com/media/papers/2553 in the sample robot code zip file. Here's more or less how it works: Let's say you command your canon to 355 degrees and it overshoots so your sensor reads 3 degrees. For your next PID calculation, your error is 355 - 3 = 352 degrees. This is the problem you've had: it wants to command your canon to do another loop. To solve it, check your error to be within +/- 180. If not, subtract (or add, if the error is negative) 360 degrees. For this case, we subtract 360 so: 352 - 360 = -8 degrees. This will get your canon to head in the right direction by the correct number of degrees. Here's the basic algorithm: Code:
Error = desired - actual;EDIT: For your application, the while loop is unnecessary. We use it in autonomous since we allow the heading integrator to grow past 360 in both directions (i.e. we don't wrap the heading integral - we just take care of the wrap on the error term as stated above). |
Re: Programming Puzzle
While my above post solves your math issue, you may have a bigger problem.
A continuous pot has a gap in which the wiper will not contact the resister band (right where it will flip from 5V to 0V). When that happens, the A/D pin will be at a floating voltage. You may get weird voltage readings in that band depending on how the A/D pin is "wired". Is there a pull-up or pull-down resistor on your board? If not, you should definitely add one so when the wiper loses contact, you have a defined voltage that is either 0V or 5V (not somewhere in between). |
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