Chief Delphi

Chief Delphi (http://www.chiefdelphi.com/forums/index.php)
-   Pneumatics (http://www.chiefdelphi.com/forums/forumdisplay.php?f=54)
-   -   Physics/Engineering/Math Problem (http://www.chiefdelphi.com/forums/showthread.php?t=124612)

Jengles 13-01-2014 23:55

Physics/Engineering/Math Problem
 
Currently I am trying to solve for the maximum amount of force a 16" stroke of a piston could take sideways before it were to break. I'm kind of clueless where to begin.

Ether 13-01-2014 23:58

Re: Physics/Engineering/Math Problem
 
Quote:

Originally Posted by Jengles (Post 1326809)
Currently I am trying to solve for the maximum amount of force a 16" stroke of a piston could take sideways before it were to break. I'm kind of clueless where to begin.

Let me guess: you want to use the cylinder rod as a side-loaded latching mechanism for your kicker/catapult.



MechEng83 14-01-2014 00:13

Re: Physics/Engineering/Math Problem
 
Quote:

Originally Posted by Ether (Post 1326812)
Let me guess: you want to use the cylinder rod as a side-loaded latching mechanism for your kicker/catapult.

If this is actually why you're asking, our team did this on a mechanism in a previous year. I recommend not using the shaft as the locking mechanism, but thread an extension on made out of grade 8 material, then support it as closely as possible on both ends.

"break" is a loosely defined term. Typically it would mean fracture, but in the case of a rod extension from a piston, any permanent deformation (yielding) from bending, or something biting into the shaft would be detrimental to the future operation of the shaft.

If you know the bending moment on the shaft, you could use the formula sigma=M*c/I where c is the radius, and I is the second moment of area. I=pi/2*r^4. Then compare the stress value (sigma) against the yield limit of the steel in the rod extension.

Jengles 14-01-2014 00:20

Re: Physics/Engineering/Math Problem
 
Quote:

Originally Posted by MechEng83 (Post 1326819)
If this is actually why you're asking, our team did this on a mechanism in a previous year. I recommend not using the shaft as the locking mechanism, but thread an extension on made out of grade 8 material, then support it as closely as possible on both ends.

"break" is a loosely defined term. Typically it would mean fracture, but in the case of a rod extension from a piston, any permanent deformation (yielding) from bending, or something biting into the shaft would be detrimental to the future operation of the shaft.

If you know the bending moment on the shaft, you could use the formula sigma=M*c/I where c is the radius, and I is the second moment of area. I=pi/2*r^4. Then compare the stress value (sigma) against the yield limit of the steel in the rod extension.

What is M?

MechEng83 14-01-2014 00:32

Re: Physics/Engineering/Math Problem
 
Quote:

Originally Posted by Jengles (Post 1326823)
What is M?

M is the aforementioned "bending moment"

The formula for calculating it will depend on your endpoint support configuration, e.g. fixed-fixed, fixed-free, fixed-pinned, pinned-pinned (pinned-free and free-free are dynamic cases, and the math becomes a whole lot more fun) Try here for a tutorial in calculating bending moment.

Jengles 14-01-2014 00:55

Re: Physics/Engineering/Math Problem
 
Quote:

Originally Posted by MechEng83 (Post 1326832)
M is the aforementioned "bending moment"

The formula for calculating it will depend on your endpoint support configuration, e.g. fixed-fixed, fixed-free, fixed-pinned, pinned-pinned (pinned-free and free-free are dynamic cases, and the math becomes a whole lot more fun) Try here for a tutorial in calculating bending moment.

So what would the equation/set up look like for a fixed-free configuration?

MechEng83 14-01-2014 10:30

Re: Physics/Engineering/Math Problem
 
Assuming the load is perpendicular to the shaft, the maximum bending moment for a fixed-free setup occurs at the fixed end and is calculated by multiplying the force by the distance from the fixed point. There is no bending moment between the load and the free end.

Mike Schreiber 14-01-2014 16:53

Re: Physics/Engineering/Math Problem
 
1 Attachment(s)
I've attached a semi worked out solution. You should be able to plug in your numbers to these equations. I assumed the shaft is 6.35 mm or 1/4 in stainless steel. I don't know what it is actually made of but you want to look up the yield stress. Once you solve for the moment, that is equal to force applied * distance cantilevered. If you need more help just ask.

Ether 14-01-2014 16:58

Re: Physics/Engineering/Math Problem
 
Quote:

Originally Posted by Jengles (Post 1326809)
Currently I am trying to solve for the maximum amount of force a 16" stroke of a piston could take sideways before it were to break. I'm kind of clueless where to begin.

I think you should post a picture or hand-sketch of what you are proposing to do to your piston so that there is no miscommunication.




All times are GMT -5. The time now is 16:34.

Powered by vBulletin® Version 3.6.4
Copyright ©2000 - 2017, Jelsoft Enterprises Ltd.
Copyright © Chief Delphi