| rnewendyke |
26-05-2014 23:53 |
Re: Physics of T-boning
Quote:
Originally Posted by DampRobot
(Post 1387461)
I think the physical description of T boning described by this thread (including by me) is sort of incomplete. Why should it be easier for 971 with their octagonal frame to get out of pins than a rectangular bot of the same dimensions (and same drivetrain, same bumper fabric, etc)?
There's obviously some minimum torque needed to break off the bumper of the pinning robot, and shortening the length of the bumper against the pinning robot reduces this torque. But I'm still not sure exactly how it works.
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On a rectangular frame perimeter when a robot goes to t-bone you, they are hitting you perpendicular to the direction your wheels roll (otherwise described as your wheel base). The portion of your bumper that they are in contact with is perpendicular to your wheel base, so as you try to drive out of the t-bone theoretically speaking 100% of the frictional force opposes your robot. In the case of 971, whose frame perimeter is not rectangular and have bumpers that are not perpendicular to their wheel base, 100% of the frictional force does not oppose their robot when contacted on one of the angled sides of the bumpers.
cos( Θ ) * frictional force = frictional force opposing your robot's motion
Θ = the angle between the plane of contact between the two robots' bumpers and the direction of your wheel base
Interestingly enough as a robot attempting to t-bone 971 on one of the angled sided of their bumper, you apply a force on their robot in the direction that they would be driving in to get out of the t-bone, effectively helping them escape the t-bone you are attempting to put them in.
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