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-   -   Mecanum Wheel Speed Reduction (http://www.chiefdelphi.com/forums/showthread.php?t=132216)

yarden.saa 06-01-2015 02:22

Mecanum Wheel Speed Reduction
 
Hi CD,
I would like to know what speed reduction do you reccomand for 6" mecanum with one cim motor per wheel.
We used to have 9:1 - 13:1 with 6" wheel in tank drive.

Mike Marandola 06-01-2015 02:28

Re: Mecanum Wheel Speed Reduction
 
Quote:

Originally Posted by yarden.saa (Post 1422549)
Hi CD,
I would like to know what speed reduction do you recommend for 6" mecanum with one cim motor per wheel.
We used to have 9:1 - 13:1 with 6" wheel in tank drive.

We will most likely go with 10.5:1 which will give us about 10.7 ft/s adjusted.

Ben Martin 06-01-2015 09:02

Re: Mecanum Wheel Speed Reduction
 
This is totally contextual, but I look at past successful robots for years with "field dividers" (2010, 2012) that have their speeds posted to try to pick a reduction. We'll likely go 11-12 ft/s max.

electroken 06-01-2015 15:23

Re: Mecanum Wheel Speed Reduction
 
Quote:

Originally Posted by yarden.saa (Post 1422549)
Hi CD,
I would like to know what speed reduction do you reccomand for 6" mecanum with one cim motor per wheel.
We used to have 9:1 - 13:1 with 6" wheel in tank drive.

In 2013 we used 6" Vex-Pro Mecanums with one CIM per wheel. The gearbox ratio we eventually settled on was 8.45:1. If fact, we're using that robot to determine this years needs.

Ether 06-01-2015 16:29

Re: Mecanum Wheel Speed Reduction
 

Here's the formula for vehicle free speed at motor free speed:

V = (N*pi*D)/(720*G) feet/sec

N is the motor free speed in RPM.

G is the motor revs per wheel rev (i.e. includes gearbox and sprocket or pulley reduction)

D is the wheel diameter in inches.

A rough rule of thumb1 is to multiply V by ~80% to account for various friction forces to obtain vehicle top speed at full throttle.


1originating I believe with JVN. The actual fudge factor depends on your drivetrain design and workmanship.


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