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LED bulb question
Two different LED bulb models by the same manufacturer. Packaging says: bulb1: 800 lumens, 2700K, 150 mA @ 120V, 8.5 watts bulb2: 800 lumens, 2700K, 120 mA @ 120V, 10 watts Can someone explain what's going on here? |
Re: LED bulb question
The two bulbs might operate at different power factors (PF).
Power factor is defined as the ratio of power (Watts) consumed to apparent power (Volt-Amperes) drawn. Resistors and old-fashioned incandescent light bulbs operate at unity power factor, because all the current they draw follows the applied voltage instantaneously; no lag, no distortion. Inductive loads such as transformers and AC motors operate at less than unity power factor because their current draw lags the applied voltage. Electronic loads, such as the AC to DC converter circuits inside LED light bulbs, operate at less than unity power factor because their current draw is distorted relative to the line voltage. But, not all AC to DC converter circuits are created equal; some distort more than others, so some operate at lower power factor. The first bulb in your example operates at PF = 8.5 / (120 x 0.15) = 0.47 The second bulb operates at PF = 10 / (120 x 0.12) = 0.69 It would be worthwhile to test these two bulbs using an inexpensive meter such at the Kil-A-Watt, to see how well actual performance tracks their markings. |
Re: LED bulb question
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The other question is one a dimmable and the other not? I had an interesting experience recently when I installed a non-dimmable LED bulb in a fixture that was connected to a lighted switch. Turned on the switch and everything worked fine. Then I turned off the switch and periodically the bulb would flash on for a very short period. Scratching my head and then looking at the lighted switch the light in the switch would flicker corresponding to the bulb flashing. I later put a dimmable bulb in that fixture and the flashing stopped. In retrospect I concluded that the slight voltage leak through the switch's illumination allowed the capacitor in the non-dimmable bulb to charge to the point where current would flow through the LED. It would then drain the capacitor, the light would go off, the capacitor charge again and the cycle repeat. So a dimmable bulb would have higher consumption at the same light output due to the added control circuitry's power consumption. But that of course does not explain why the math doesn't calculate out. |
Re: LED bulb question
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Bulb2 is dimmable; bulb1 is not. Quote:
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Re: LED bulb question
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I happened to have two Cree LED bulbs marked 2700K 800 Lumens 9.5W 120V 60 Hz 79 mA on hand. From my household 120V, both draw about 8 Watt, 70 mA, and both measure PF = 0.88 using my Kil-A-Watt. Their markings indicate ~unity power factor: 9.5W / (120V x 79mA). Small print also says they are UL Listed and suitable for damp locations. Another marking 2213 suggests they were manufactured in Week 22 (late May/early June) of 2013. What brand are your LED bulbs? |
Re: LED bulb question
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They were selling them for 82 cents a piece so I picked up a dozen. |
Re: LED bulb question
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I picked up a Kill-A-Watt yesterday. I tested it with a standard* 60 watt incandescent bulb in an outlet whose voltage reads 123.6 V. The Kill-A_Watt says it's drawing 33.9 watts / 33.9 VA (PF=1) and 0.27 A. I had not expected that. Would you please test a standard* 60 watt incandescent bulb with your meter? * i.e. not "long life" |
Re: LED bulb question
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Re: LED bulb question
I just tested a 750/1500 watt dual heat resistive space heater with the Kill-A-Watt. The readings made sense. Power Factor 1.00 (as expected), and watts approximately 765 (on low) and 1443 (on high). When I get a chance, I'm going to test a larger sample of incandescent light bulbs of various brands and power ratings. |
Re: LED bulb question
I just tested three GE Reveal incandescent light bulbs with my Kil-A-Watt.
The 29W bulb measured 28 Watts, 0.23 Ampere, 1.0 power factor. The 60W bulb measured 60 Watts, 0.5 Ampere, 1.0 power factor. The 75W bulb measured 76 Watts, 0.63 Ampere, 1.0 power factor. As expected. |
Re: LED bulb question
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Do you have any GE Soft White bulbs? If so, could I ask you to test them? |
Re: LED bulb question
What about the LED bulbs that started this discussion, have you tested them? Inquiring minds want to know.
I do have to wonder if there is a problem with Ether's Kill-a-watt in accurately measuring at the lower end of the range. I was under the impression that the difference between the standard, soft white and reveal bulbs was purely the coating on the inside of the glass and not due to a different filament. So in theory they should all match their wattage ratings within the expected tolerance of a high volume mass produced item at low price point. How about plugging a power strip in with that heater on low and a lamp with the bulb and comparing the results with and without the bulb on? |
Re: LED bulb question
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34.2W bulb only (60 watt soft white incandescent) 755W heater only 811W heater plus bulb 811-755 = 56W Power Factor was 1.00 for all readings above. Quote:
I think I may have a defective unit. |
Re: LED bulb question
I was thinking about the bulb's tolerances, but the Kill-a-watt's tolerance is an important part of the equation as well.
Is there anything in the documentation that would indicate the tolerance is different at different parts of the range? If it is just a stated .2% then I'd have to agree that you seem to have a defective unit based on Richard's results with his. +/- 1 Watt seems to be as good as would be expected on a product like an incandescent bulb. |
Re: LED bulb question
Have you tried measuring the bulb resistance with a DVM?
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Re: LED bulb question
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So even if 0.2% means 0.2% of 1800, the unit is still way out of spec. |
Re: LED bulb question
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I don't have a DVM that uses 120 volts to measure resistance. . |
Re: LED bulb question
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Re: LED bulb question
I just called the tech support number and the friendly fellow who answered wasn't able to shed any light on the situation. . |
Re: LED bulb question
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Richard, If you are still following this thread, could you please take a peek at the label on the back of your Kill-A-Watt and compare it to this and flag any differences for me? Note especially the red arrows. I'm wondering if your unit is an improved version. I bought mine at Menard's, and they appeared to have been hanging on the rack for quite some time (packaging covered in fine dust). Also, the printing on the cardboard label inside the thermal-welded plastic packaging is copyright 2011. |
Re: LED bulb question
Data point: My Kill-a-watt is wildly inaccurate at very low (< 10W) power levels: Some of my light bulbs don't even register any reading. (This is based on measurements more than a year ago. I should try to repeat them now).
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Re: LED bulb question
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Mine is also marked Conforms to UL STD. UL 3111-1, yours is 61010-1 Mine is marked Voltage: 125VAC Power: 1875VA, yours is 120VAC, 1800W |
Re: LED bulb question
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Re: LED bulb question
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Here's my working hypothesis: to get the price down and appeal to a larger market, the newer model (4400.01) uses cheaper components with larger tolerances. Quote:
Also, could you try your unit with a 60W incandescent bulb and tell us what the Watt readout says? |
Re: LED bulb question
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The cold resistance gives you a reference to tell if things are really strange. You can also make some assumptions and do a little math and see if a simple physics model matches reality. Tungsten (assuming your filament is really tungsten) has a resistance temperature Cef of 4.5E-3 at 20C. (Assuming it is linear all the way to white hot is a big assumption at least for me.) Using 120 VAC for the rated voltage 2500K as the bulb temp and a little excel math I get about 22 ohm cold. Am I close? Of course with a 240ish ohm hot resistance the cold resistance doesn't tell you that much without a tested model. |
Re: LED bulb question
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The cold resistance of 60W soft white incandescent bulb measures approx 18 ohms. Don, if you're still reading this thread: does the label on the back of your Kill-A-Watt say model P4400 (like Richard's) or P4400.01 (like mine) ? |
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