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-   -   Ok, this does not make sense.... (http://www.chiefdelphi.com/forums/showthread.php?t=40097)

Michael Hill 18-10-2005 20:41

Ok, this does not make sense....
 
I have proven that .9... = 1. (If you want the proof, just tell me)

but what about the floor() function?

wouldn't the floor(.9...) = 0 and the floor(1) = 1?
Therefore disproving my proof?

Ryan M. 18-10-2005 20:45

Re: Ok, this does not make sense....
 
Yes, that does disprove you.

I'd love to see the proof, but it's undoubtedly like the proofs that prove 1=2. Hate to say it, but .999... isn't equal to 1, unless you're an microprocessor.

--EDIT--
Yeah, so there's a proof. Big whoop. Sigma is overrated. ;)

Bcahn836 18-10-2005 20:48

Re: Ok, this does not make sense....
 
Maybe this would help. . .
Linky

Michael Hill 18-10-2005 21:00

Re: Ok, this does not make sense....
 
Summation was the way I proved it. Any thoughts on if floor(.9...) = 1 or 0?

mechanicalbrain 18-10-2005 21:25

Re: Ok, this does not make sense....
 
Quote:

Originally Posted by Bcahn836
Maybe this would help. . .
Linky

Or.... if your too lazy to read through that (like me!)

3/9= .3333333.... so 3/9 + 3/9 + 3/9 = 9/9 and .3333333.... + .3333333.... + .3333333.... = .999999....

Isn't infinity wonderfull?

Kevin Sevcik 19-10-2005 09:52

Re: Ok, this does not make sense....
 
You'd need a more formal definition of floor before you can prove or disprove anything. The formal definition of floor is: floor(x) is equal to the largest integer less than or equal to x.

You've already proven that .999... = 1, so 1 is the largest integer less than or equal to .999... and everything works out. Confusion only comes when you use the informal definition of ignoring everything after the decimal point.

coastertux 19-10-2005 17:42

Re: Ok, this does not make sense....
 
x = 0.9999...
10x = 9.9999...
10x - x = 9.9999... - 0.9999...
9x = 9
x = 1


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