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Homework help?!
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Attachment 6412
Does anyone know how to find the diameter? It appears the lack of sleep is getting to me. Chord BD=8, and minor arc BA=60 degrees |
Re: Homework help?!
If I remember geometry, BD is perpendicular to BA, so the diameter (DA) is 8/(cos(30))
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Re: Homework help?!
To confirm his answer in a complicated round about way:
Line Seg BC would create an iscoceles triangle because two sides are equal to the radius. Using laws of sine 8/sin (120) = r/sin30 therefore d=2(8sin(30)/sin(120)) If you evaluate you get the same number approximately 9.237 or 16/(sqrt(3) or rationalized 16sqrt(3)/3 Hope I helped haha |
Re: Homework help?!
Quote:
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Re: Homework help?!
Another much simpler way is to form a 30-60-90 triangle BDA which allows you to find DA by dividing the segment BD by 2, and then times that by root 3 to find the length BA, which is the diameter.
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