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Math Help
I searched, to no avail, however my time is limited.
I have the equation: x = (1+e^y) / (1-e^y) and I need to solve for y. Using the TI, I get the solution as: y = ln( (x-1) / (x+1) ) But I need to know how to do it by hand. I took Calculus 1 so long ago, I just simply forgot the steps. Any assistance would be much appreciated. Thanks! Jacob |
Re: Math Help
Correct me if I'm wrong, but this seems right:
x = (1 + e^y) / (1 - e^y) x(1 - e^y) = (1 + e^y) x - x(e^y) = 1 + e^y x - 1 = e^y + x(e^y) x - 1 = (x + 1)(e^y) (x - 1) / (x + 1) = e^y y = ln( (x - 1) / (x + 1) ) first post =P |
Re: Math Help
How is this step performed?
x - 1 = (x + 1)(e^y) Nvm, I just realized. THANK YOU VERY MUCH! Very nice first post! Welcome to the CD community! ~Jacob |
Re: Math Help
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x - x(e^y) = 1 + e^y x - 1 = xe^y + e^y factor the e^y out x -1 = (x + 1)(e^y) |
Re: Math Help
m^3, Joe and Greg, you guys ROCK!
I'm tutoring Calculus, and I was helping a student when we ran into this section of a problem. By the way, is there a math help thread that I'm, missing (cuz I did search), or is math help something new here? Jacob |
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I hope that all of our new members are as helpful as the one above. We will be in for an amazing season if that is the case.
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Re: Math Help
Thanks!
I hope it will be an amazing season too; with the new control system, I'm anxious to see what they do with the game (autonomous, etc...). I actually meant to put those steps in... Edited my post right as you asked =P Is there a math thread? I don't know... If I have trouble, typing equations into Google sometimes yields similar equations that can help you solve the original. Michael |
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My brother got me a book of mathematical lookup tables for Christmas one year, since I was destined to go so far in math. First year of college, my girlfriend at the time swapped her TI-89 for my TI-83 since she her course was teaching exact steps for a TI-83, and I wanted a TI-89 for Calc. I havne't used that book ever since. Unfortunately, I've also forgotten some of the more rudimentary algebraic tricks -- like I know there's an expression you can multiply the top and bottom of the original equation by in order to *easily* extract the y from it -- but I can't remember the trick to figure it out :o |
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