![]() |
Mentors, Be careful what you teach your Future Engineers
|
Re: Mentors, Be careful what you teach your Future Engineers
That was pretty awesome, must say that the time and money spent on it should have gone to a FIRST team ^_^
|
Re: Mentors, Be careful what you teach your Future Engineers
Here I was, expecting to see trouble coming, now I'm ROFLMBO. Excellent!!!
I think I'll watch it again.:D |
Re: Mentors, Be careful what you teach your Future Engineers
Quote:
Pretty sweet, I have to say! |
Re: Mentors, Be careful what you teach your Future Engineers
That's either REALLY, REALLY COOL or some pretty good video editing.
I notice that they don't really show the base of the structure. That's probably a good thing. |
Re: Mentors, Be careful what you teach your Future Engineers
Quote:
|
Re: Mentors, Be careful what you teach your Future Engineers
Quote:
|
Re: Mentors, Be careful what you teach your Future Engineers
Today has been a naste day at work. That brought out a little smile.
|
Re: Mentors, Be careful what you teach your Future Engineers
Quote:
Just like CNN's "holograms". They may be funny, but they are all fake. :rolleyes: |
Re: Mentors, Be careful what you teach your Future Engineers
Quote:
|
Re: Mentors, Be careful what you teach your Future Engineers
As long as were playing the "Is this even possible" game, here comes the math:
As long as v^2/r is greater than gravity, you can make the loop. The kicker on a passenger train is that r actually has to be pretty large (Trains are not terribly flexible in the vertical plane). Just to see the math, if r=100feet the loop would be at least 200 feet tall (That puts it up there with some of the tallest coasters). v^2/100>32.2 ft/s^2 therefore V^2 = 3220 and thus v would be about 57 ft/s which is about 40mph. Now that is the speed at the peak. Assuming that the train has low power to weight ratio you can figure the entrance speed required to do the loop. The looh height H times Gravity times the mass (mgH) will equal the change in kinetic energy between the top and the bottom (0.5*m*V1^2 - 0.5*m*V2^2). Mass cancels out so gH=0.5*(V1^2-V2^2) This means 12880=(V1^2-57^2) therefore V1^2=12880+3220... V1=126ft/s = about 87mph So obviously this is nearly impossible because Back to the Future 3 showed us that if a train hits 88mph you will end up in the past or future, or some sort of alternate universe.:ahh: |
Re: Mentors, Be careful what you teach your Future Engineers
Alternatively, just pause the Youtube video as the train is going around the loop. You can tell that it's computer generated because the train and structure look, well, computer generated.
|
Re: Mentors, Be careful what you teach your Future Engineers
hahah, very nice. Although this video has been posted on here before. I remember but I don't recall who posted it.
|
Re: Mentors, Be careful what you teach your Future Engineers
http://what-if.xkcd.com/43/
I really love xkcd, and the What-if sections are some of my favorites. I just saw this one and had to dig up this thread. |
Re: Mentors, Be careful what you teach your Future Engineers
The link now gives:
"future engineer-..." The YouTube account associated with this video has been terminated due to multiple third-party notifications of copyright infringement. Anyone have a link to another copy, so I can see what all the ROFLing is about? |
| All times are GMT -5. The time now is 13:30. |
Powered by vBulletin® Version 3.6.4
Copyright ©2000 - 2017, Jelsoft Enterprises Ltd.
Copyright © Chief Delphi