![]() |
Team 2526 - Propeller Propulsion Prototype.
|
Re: Team 2526 - Propeller Propulsion Prototype.
try a condensor fan from an airconditioner, works great;)
|
Re: Team 2526 - Propeller Propulsion Prototype.
Have you tested to see if it (or 4 of them) can generate enough force to move your robot?
|
Re: Team 2526 - Propeller Propulsion Prototype.
Have you measured the thrust this produces?
|
Re: Team 2526 - Propeller Propulsion Prototype.
Quote:
|
Re: Team 2526 - Propeller Propulsion Prototype.
Can some other team argue that this interferes with their robot's movement? Just curious.
If it has enough thrust to have any effect on your robot, then why not on the robot in front of you? Anyone? |
Re: Team 2526 - Propeller Propulsion Prototype.
Quote:
|
Re: Team 2526 - Propeller Propulsion Prototype.
Quote:
Anyone? =P |
Re: Team 2526 - Propeller Propulsion Prototype.
Quote:
It was a serious question. |
Re: Team 2526 - Propeller Propulsion Prototype.
Quote:
|
Re: Team 2526 - Propeller Propulsion Prototype.
Quote:
I mean, it is part of our plan to abuse the fact that we might be able to blow balls away from our trailer, but really, nothings stopping any other team from making a fan, right? =) |
Re: Team 2526 - Propeller Propulsion Prototype.
Quote:
|
Re: Team 2526 - Propeller Propulsion Prototype.
Quote:
|
Re: Team 2526 - Propeller Propulsion Prototype.
Quote:
woot, 1403 post, Cougar Robotics |
Re: Team 2526 - Propeller Propulsion Prototype.
To return to the original point of the message. Thank you for the demonstration--while you don't have a newton meter avaliabe it is very simple to build something which will have a similar effect. Take a box and suspend it making a pendulum (longer suspension will mean greater accuracy), mount your fan set up on it and let her rip. By measuring the angle off normal created when your fan is turned on and using a simple bathroom scale to measure the mass of the box and your fan set up you will have more than enough accuracy. Here's the math:
Fractional force of gravity pointing in the horizontal direction: Fgx Force due to gravity: Fg Angle created by string from normal: theta Fgx=Fgsin(theta) By inspection Fprop=Fgsin(theta) Note that this lets you give a force in Lbs which are much nicer than newtons. |
| All times are GMT -5. The time now is 00:00. |
Powered by vBulletin® Version 3.6.4
Copyright ©2000 - 2017, Jelsoft Enterprises Ltd.
Copyright © Chief Delphi