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G17 Algorithm
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Re: G17 Algorithm
No you have until the clock reads 0 to get the ball back on the field. You are solving for the time on the clock, not the time you have to move the ball.
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Re: G17 Algorithm
Incorrect.
T expire (x) = T now – { 11 + (4 * # unexpired balls currently in Station) } T expire is the time at which the penalty is applied. So, you put a ball in at 15 seconds left. Texpire = Tnow-{11+4*unexpired)} Tnow is 15. We will assume an empty alliance station (unexpired = 0). Texpire = 15-(11+4*0)=15-11=4. They have until the timer reads 4 seconds left to put the ball back out. For reference, the DOGMA document on the FRC website will help understand the algorithm. It is at http://usfirst.org/uploadedFiles/Com...sets/DOGMA.pdf |
Re: G17 Algorithm
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In this case, the unexpired balls would be 0, because you are assuming that there aren't any balls in the station until the ball rolls into the station. |
Re: G17 Algorithm
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Re: G17 Algorithm
What happens if a ball is scored at 1 second? Is there some point were the system stops? I'm guessing that any ball scored after 11 seconds wouldn't need to be put back into play. Please don't show me any formulas, i'm just a dumb parent that can't figure this out.
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Re: G17 Algorithm
no. Once you get down to 11 seconds you would have until 0 secs to get the ball back... and once 0 seconds is hit, you cannot receive a penalty. Therefore, the ball doesn't have to be returned.
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Re: G17 Algorithm
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Re: G17 Algorithm
Ok, but this is getting pretty annoying. It seems like there's about 5 threads all about G17. PLEASE look at other threads before starting a new one and add on to the other if it's related.
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