![]() |
Re: pic: 2010 window motor winch
I have to agree with Tom about the great explanation from Joe, but, show some mercy on a software guy and explain the formula use to calculate the 54W below.
TIA Quote:
|
Re: pic: 2010 window motor winch
Quote:
|
Re: pic: 2010 window motor winch
Quote:
120lbf * 3ft = 488 J (Work = Force*Distance, there's a conversion factor from lbf-ft to J in here as well. Google Calculator did this conversion for me) 488J/ 10s = 48.8W (Power = Work/Time) 48.8W / .9 = 54 W (Gearbox efficiency) From what I remember reading here and erring on the side of caution I would use 80% as the gearbox efficiency yielding 61W of power necessary. Also be careful using 120lb as a weight. A full 120lb robot this year could end up at over 150lb after adding battery and bumpers. Using 150lb and 80% efficiency you need about 76W of power to complete the lift in that time. |
Re: pic: 2010 window motor winch
But you have to account for the bumpers and batt
|
| All times are GMT -5. The time now is 03:41. |
Powered by vBulletin® Version 3.6.4
Copyright ©2000 - 2017, Jelsoft Enterprises Ltd.
Copyright © Chief Delphi