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Unread 30-01-2011, 21:41
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Re: Stalling the BaneBot 775 motors

For the purpose of this discussion I think we are getting too far into the theory behind the component. It would be a very difficult piece of hardware to work with if it only output 4% power when you tell it to give 20%. For the purpose of this discussion and our use, I am quite sure that the Jaguar compensates for the exponential effects of Inductance/switching frequency/rise time and changes its pulse frequency so that the output power varies linearly with the input instructions. In this case, an instruction of 20% output would result in an intuitive 20% power (W) output and thus ~200W.

If the jaguar input controlled the switching frequency- linearly, then I think Ether is right. After one of our team members hooked up a jaguar backwards today, I opened it up to take a peek inside. The output has a capacitor on it- I believe this would effectively "smooth" the output power and generate a physically lower voltage/amperage. With the capacitance/inductance/resistance and switching frequency you effectively have an RLC circuit. Relative to the switching frequency, output would indeed change exponentially just like Ether's calculation.

I believe we are just thinking of two different parameters of which we are commanding 20% thereof- My thinking is that the input commands control the power output wheras Ether's thinking is that the input commands control the switching frequency. I'm going to stick with the former so tell Regis my final answer is ~200W!

If you know what the frequency is (someone with an oscilliscope?), we know what the percieved output voltage, current and resistance is at full power, I can take a look at the guts of the Jag and see what the capacitance is. Can we not deduce the inductance?
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Last edited by fox46 : 30-01-2011 at 21:45.