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Re: 3 outputs for 2 booleans
Thats the hard to understand way. The easy way to do it is to build an array (Build Array) and then put that array into a number (Boolean Array to Number) then put that number into a case structure (that will change the true/false selector to a 0, Default/1 selector). Now it helps to know binary at this point. You right click the selector and add a case after. Do this until you have 4 cases (0, Default; 1; 2; and 3). If both booleans are off the case is 0 (false, false). If boolean 1 is on and 2 is off the case is 1 (true, false). If boolean 2 is on and 1 is off the case is 2 (false, true). If both are on the case is 3 (true, true). See the attached picture for wiring.
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It's not normally a good idea to give a programmer a drill but rules are made to be broken.
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