View Single Post
  #14   Spotlight this post!  
Unread 10-02-2011, 02:22
John G John G is offline
Registered User
FRC #0399 (Eagle Robotics)
Team Role: Programmer
 
Join Date: Nov 2009
Rookie Year: 2009
Location: Lancaster, CA
Posts: 72
John G is on a distinguished road
Re: pic: In_CIM_erator

Quote:
Originally Posted by AdamHeard View Post
Mechanical power is torque x speed.

Stepping down from 18 to 12V is a 2/3 change.

Power = 2/3Torque x 2/3 speed. Works out to the power at 12V being 4/9 that of 18V.
Ok. I did Power = w/t; w = Fd; F = torque *r. I thought distance and time would stay constant, so I ended up with 2/3 by just changing the torque. Thank you.
Reply With Quote