Quote:
Originally Posted by Ether
16.8 watts max power output w/o gearhead
= 12.4 ft-lb/sec
x2 motors = 24.8 ft-lb/sec max power output
2.3 lb estimated robot weight
(24.8 ft-lb/sec) / (2.3 lb) = 10.8 ft/sec (neglecting friction)
|
Continuing the calculation:
(16.8 watts @ max power)/(0.0475 Nm torque @ max power) = 353.7 radians/sec shaft speed @ max power
(10.8 ft/sec)/(353.7 radians/sec) = 0.03045 ft shaft radius = 0.73 inch shaft diameter (for direct drive)
Probably want to reduce that diameter by 15% or so for losses and margin
someone please check my math