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Re: Calling all Mechs! (Torque calculations)
Taking your assumptions to be correct, i.e.:
uF = 1.4
normal force = 75lbs
wheel OD = 3in =1.5in radius
radius of pin shear = 3/16 (you can compute the larger radius, but the shear forces will be lower)
Max Torque = 75lbf*1.4*1.5in = 157.5in*lbf
Shear force per pin jct = torque/ radius of pin shear/2 = 157.5in*lbf/0.1875in/2 = 420lbf
Or 840lbf in double-shear.
This sounds all well and good, but this pin will need a press-fit between the hub and shaft that it is connecting, otherwise all bets are off. This calculation is incredibly simplistic and does not come near to mimicking the loads your drive train will see. Impulse loads could shatter a hardened pin, the hole drilled out of the 3/8 shaft will weaken it, I don't see this ending well, but I may be wrong.
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