Thread: CIM Motor RPM
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Unread 11-11-2011, 21:17
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Re: CIM Motor RPM

Quote:
Originally Posted by EricH View Post
Let's assume 6" wheels (3" moment arm), and 4 wheels, each with its own CIM. 150/4=37.5 lbf per wheel supported (which we'll call N). At 3", assuming a coefficient of friction (mu) of 1 (F=N*mu), that's 112.5 lbf-in of torque exerted on the wheel (F*d). That converts into 1800 oz-in to get moving at all.
The 1800oz-in number is the max wheel torque that can be supported before you lose traction... not the torque required to start moving the vehicle.


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