Thread: Bearing Block Question
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Unread 19-12-2011, 13:19
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AKA: Robert Cory Molloy
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Re: Bearing Block Question
Quoted from Phalanx from Team 1089

Quote:
Chain pitch is either .250 (#25) or .375 (#35)

Formula for Center to Center Distance of Sprockets:
(B1/8) * (2*B4-B2-B3 + SQRT((2*B4-B2-B3)^2-(8/3.14159^2)*((B2-B3)^2)) )
B1 = chain pitch
B2 = Sprocket 1 teeth
B3 = Sprocket 2 teeth
B4 = # Whole Links

Formula for Number of WHOLE Links:
(2*E4/E1+E2/2+E3/2+((E2-E3)/(2*3.14159))^2/(E4/E1))
E1 = chain pitch
E2 = sprocket 1 teeth
E3 = sprocket 2 teeth
E4 = Center distance
These two formulas should help you actually determine the correct length for the perfect chain to not have tensioning. It should, somewhat, help your chain popping problems. Many teams run #25 chain for their drives and its possible to do. The right calculations just need to be brought in if not done so already.
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