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Re: Motor Quiz
My work:
CIM Motor Constants
442.5 RPM/Volt
2.581954 oz-in / A
Resistance of motor windings is 0.0902255639 Ohms by Ohm's Law
Thus:
60 oz-in requires 23.238214 A to stall, from a 2.09668 V source
Also, it takes 8.3615819 V to spin 3700 RPM under no load
Add the voltages to arrive at 10.458 V needed to spin 60 oz-in load at 3700 RPM
Check: At this voltage:
Free speed is 4627.65 RPM
Stall Torque is 299.2731 oz-in
Operating parameters are at:
20.0486% of stall
79.9514% of free speed = 3699.87 RPM
Less than 0.4% Calculation error.
Can someone tell me if this is the proper way to do this, or if my hairbrained idea just happened upon a lucky coincidence?
__________________
Teacher/Engineer/Machinist - Team 696 Circuit Breakers, 2011 - Present
Mentor/Engineer/Machinist, Team 968 RAWC, 2007-2010
Technical Mentor, Team 696 Circuit Breakers, 2005-2007
Student Mechanical Leader and Driver, Team 696 Circuit Breakers, 2002-2004
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