Quote:
Originally Posted by sanddrag
I arrived at my answer by a very different (and probably incorrect) method from the poster above. I figured motor constants for RPM/Volt and Oz-In/Amp, found how much current it would take to hold 60 oz-in at stall, considered the resistance of the motor's windings, then figured out how many volts it would need to hold 60 oz-in at stall, then I figured how many volts it would need to spin 3700 RPM at no load, then added those two voltages to arrive at my answer.
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The above method is arithmetically identical to what Aren did:
current to hold "D" oz-in at stall = (D/B)*Istall
volts to hold "D" oz-in at stall = (D/B)*Istall*R = (D/B)*Istall*(12/Istall) = 12*(D/B)
volts to free-spin at "C" rpm = 12*(C/A)
adding these 2 gives:
"mystery volts" = 12*(C/A+D/B)