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Unread 16-01-2012, 02:00
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AKA: Tom Indelicato
FRC #0811 (The Cardinals)
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Join Date: Jul 2008
Rookie Year: 2005
Location: Nashua, NH
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Re: Optimum Ball Mechanics

Quote:
Originally Posted by Matt H. View Post
It's often a good idea to gear your motors for peak efficiency, which in the case of the CIM means 4614 RPM at 45 oz-in of torque.
This may be me being stupid and missing something, but how exactly do you go about gearing motors for peak efficiency? I get that at 4614 RPM with 45 oz-in of torque you'll get the maximum power output from a CIM, but say I'm gearing up a thrower, how would I actually go about this? Do I have to account for the resistance of throwing the ball as the torque and calculate out what that will put on the motor?
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