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Re: Physics Quiz 8
Energy in the system = F^2 / 2K
Length when stretched (L3) = L + F/K
Potential energy at L2 = 0.5K*(L2-L)^2
Kinetic energy @L2 = F^2 / 2K - 0.5K*(L2-L)^2
Velocity@L2 = Sqrt(2/M( (F^2 / 2K) - 0.5K*(L2-L)^2 ))
=Sqrt(2K/M( (F/K)^2 - 0.5(L2-L)^2))
I don't know what to do with that.
Last edited by lemiant : 24-01-2012 at 02:53.
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