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Unread 18-02-2012, 08:41
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Re: How to get maximum output from a Jag?

Quote:
Originally Posted by Kilo Foxtrot 7 View Post
Alright so I'm the Mech in question.

let me clear up some things

1. yes we are using 20in wheels and yes they are staggered

2. the drivetrain is running a 5:1 gear ratio on top of the 4.67:1 of the gearboxes so a total of a 23.35:1 ratio

3. i am 98.9% sure that we are not tripping the 40A breakers

4. we are using a fresh battery

so that being said is there any way to keep the jags from triping

Thx

P.S. thund plz get your facts strait before posting it saves me from wasting my valuable sleeping time. %-l
Now that we have the real gear ratios, lets go through the numbers (as a teaching exercise).

Freespeed of CIM = 5310 RPM
/60 (min / sec) = 88.5 RPS
/23.35 (gear ratio) = 3.79 RPS (rounded)
20" dia * 3.14 = 62.8" circ
62.8" circ * 3.79 RPS = 238.01" / sec
/12 (in/ft) = 19.83 ft/ sec.

These are theoretical numbers that will never be attained but typically anything over ~16ft/sec in a single speed gearsetup will trip the breakers at startup and while turning (depending on CoF, weight on wheels, wheelbase, etc).

Now lets calculate thrust.

Stall torque (again for theoretical measurements) of cim = 344 in/oz
* 23.35 (gear ratio) = 8032.4 in/oz
/20" (distance of torque) = 401.62 oz
/12 (in/ft) /16 (oz/LB) = 2.09 LBs thrust
* 4 (CIMs) = 8.367 LBf thrust

Thats low, but managable (someone check my math ... I'm terrible in the morning )

All in all your setup might work, but I'd expect tripping of the breakers when turning and in any sort of pushing match.
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