Quote:
Originally Posted by Ether
The current sense resistor would not be in the path of the inductive current if the high side were used for shunting
The inductive current would flow in a loop: through the motor, through one pair of high-side FETs, then through the other pair of high-side FETs back to the motor.
|
This is very true, but I would think only after the delay when the other half of the high side turns on.
( I hate to put this below a post like the one directly above, dsirovica that was a very good post.)