[George1902]

if you had a pyramid style stack with 4 bins on the bottom in a rectangular formation and 2 more stacked up in the center where they meet, this would be the scoring break down:

first, the stack would be worth 4 SHU. the bins are not nestled, and therefore would reach into the 4th SHU.

second, how many bins are in this stack? well, there are 4 bins at the base, and 2 in the column. therefore all 6 of these bins would count for 0 points. why? well, it's been stated a few time in this thread that any bins in the highest stack are worth 0 points. it's obvious that the top 2 are in the stack, but what about the bottom 4? well, i think the refs would rule that each of the 4 are partly suporting the 2 bins on top. so all 6 of thses bins are worth 0.

soemthing to be aware of: we've seen that in some configurations 3 bins can be worth 4 SHU if unmeshed or a bin is on it's side... well, in this case, we see 6 bins worth only 4 because multiple bins are supporting another, and therefore must be considered as part of the stack.