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0=-1 (Calculus Puzzle)
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21-03-2012, 16:19
Ether
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Re: 0=-1 (Calculus Puzzle)
Quote:
Originally Posted by
RoboDesigners
∫tan(x) dx = -1 + ∫tan(x)dx
Now subtract ∫tan(x) dx from both sides and...
0 = -1
∫tan(x)dx - ∫tan(x)dx is not equal to 0.
It's an arbitrary constant.
Ether
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