Quote:
Originally Posted by pfreivald
I suggest that you consult your local physics teacher or mechanical engineer. He/she can teach you the relationship between power, torque, and angular speed -- and how to convert that into a linear time on a 22-inch pull.
With the torque/power specifications of a particular motor/gearbox combination, you will then have all the tools necessary to make the right decision for the application.
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22lbs * 1.5 inch lever arm for a 3 inch spool = 33lbs*inch=528 oz*inch
528oz*inch / 121 (reduction in FP gearbox) = 4.33 oz*inch
RPM @ 4.33oz is approximately 19000RPM at motor, 157 RPM at output.
24 inches/s assuming 100% efficiency after the motor output.
Using specs for the 801-0673 FP