Quote:
Originally Posted by dbeckwith
I personally think that Bezier curves are the easiest to deal with
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I did some research last night and I was looking at that. However, I'm not sure as to how more efficient bezier curves are to a polynomial - only testing would tell of course.
@Ether: Your idea is great! I like its simplicity, however, I do have a question: What if I don't want the robot to move in a cubic curve? Can this method still be used to create a path that looks similar to x^(1/2) - except with a bit more curve. Also, what if the current heading angle was a slope of infinity? And, instead of using matrices (as my knowledge is extremely rustic and could use some brushing up ) could I use a Taylor polynomial instead and achieve the same result - what I mean is I have no idea how to solve for the parameters using matrices.