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That is exactly what is supposed to happen.
Think it through carefully.
As has already been discussed in several other threads, for a given number of containers the best possible score is achieved when half of the containers are on the floor and half are in the stack. Moving away from that ratio will always decrease your score. In the example you cited, the best score is 4 on the floor and 4 in the stack, for a score of 16. Making the stack higher by one container/SHU (by turning containers on end to go above the 5 SHU mark) has the effect of reducing the number of containers on the floor. By doing this, you have moved away from the optimal floor/stack ratio, and your score drops.
The important thing to realise here is that the number of containers "on the floor" plus the number of SHUs can never be more than the total number of containers in the scoring zone. If, by stacking the containers on end or edge, you build up enough extra height to go the the next SHU mark, you have effectively created a "virtual container" that has to come from somewhere. In that case, it is "virtually removed" from the containers on the floor.
-dave
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Y = AX^2 + B.... ehhh, whatever.
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