[MacZealot]

Further thoughts.

If you have 3 stacks of 5 bins, 4 bins laying scattered about the score zone, and a stack of 7 bins, this is how the score will be calculated:

[(3*5)+4] * 7

Not any other way. You don't need to bother with the 7 bins in the first half of that equation.

More examples:

You have a multiplier stack of 4 bins, and one bin lying next to the stack

1*4=4.