OK, this is probably posted somewhere here, but I can't think of where to look, or what it's even called.
Basically, I've been told that once again, the Drill Motors are faster in forward than in reverse. I remember I did something crazy with the EEPROM last year, and while it worked, it wasn't exactly efficient. So, I'm wondering if anyone knows how much faster (percentage wise) the Drill Motors are, and two, how I would make some sort of algorithm to reduce the output accordingly. I know it's possible, but I haven't had any experience with Min or Max, and I have no idea how to make "pretty" algorithms
.
So far, I know that one side would need to be reduced at all times. Depending on which the robot is going (simple if/else statement). I just need to figure out what goes on the inside of that loop, and yeah, it's confusing me a bit
. So, if anyone has the heart to help a poor confused programmer, please do
.