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Re: Motor load weight limit?
You need max torque (at stall current, unfortunately). Gear reduction (make sure it's reduction) multiplies torque (increases, just to check your answers).
for your first example, that is correct. I'll let you do the math (CIM max torque is 343 in-oz)
For the second setup, this is a little harder to do. Someone correct me if I'm wrong, but the torques for the motors in that particular toughbox should be additive (I think the issue was with the current...). I'm not going to check your math, you should know enough by now to check the total gear reduction. For calculating weight, you actually need to know the size of your spool, and that (combined with info you already know) would give you your max weight. But bewarned - this is the max weight your setup can sustain. Actually lifting is another set of equations, but this gives you an excellent upper limit (W_DNE (Weight - Do Not Exceed))
Other formulae you may find useful:
Torque = Force * Distance
This means the torque (you could call it rotational force) is given by the amount of force a lever of length Distance will exert at the end of said lever.
__________________
Nathan Hui
B.S. Electrical Engineering, UCSD '16
FRC 2473 (CHS Robotics), Team Captain '12
FTC 4950, 6038
Last edited by nathan_hui : 08-01-2013 at 23:40.
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