[Sparks333]

Hello!

You caught me Ether - that's why I shouldn't derive physics formulas a 2AM.

For people following at home, Ether modified the equation with the assumption that the frisbee can be treated as a thin disk of homogenous density - not strictly true, but definitely close enough for this sort of equation. The more general form of the equation is

I_wheel * omega_start^2 = (I_wheel * omega_end^2) + I_frisbee * (V_frisbee / r_frisbee)^2 + (M_frisbee * V_frisbee^2)

Due to the frisbee's large diameter compared to most shooting wheels, its moment of inertia is definitely non-negligible, despite having a much lower weight (moments of inertia of disks grow with the square of the radius, and linearly with mass).

Thanks for keeping me honest,

Sparks