Quote:
Originally Posted by DanielCH
How do you figure that? I'm not sure, but at this field drawing, page 69/146, it appears that the high goal has a bin that is 26 inches down, 54 inches across, and 22.5 inches deep below the gap for the goal.
That's 31,590^3 inches for Frisbee to fall into, and assuming a Frisbee is 11 inches long and wide, and 1.4 inches tall, one Frisbee is ~169^3 inches. 45*169^3=7,623^3 inches.
I could have easily made an error in my calculations, or interpretations of the field drawings, but it seems to me as if 45 Frisbees would fit into the high goal without much issue. |
It looks like you're right, thanks.
This idea is looking better and better.