I did some searching and found this
http://www.mcs.surrey.ac.uk/Personal...pi.html#arctan
arctan( t ) = t – (t^3)/3 + (t^5)/5 - (t^7)/7 + (t^9)/9 - (t^11)/11 .........
-1< t < 1
I tried it out its pretty close to what the real value is
x = tan (.5)
arctan(x) should equal .5
x – (x^3)/3 + (x^5)/5 - (x^7)/7 + (x^9)/9 - (x^11)/11 = 0.4999763883
But Surprisingle enough
x – (x^3)/3 + (x^5)/5 - (x^7)/7 + (x^9)/9 = 5.000939788
The More terms you do the more accurate your answer is
!The only problem you might run into in pbasic is memory and speed!
Cipher X