Thread: Is 'using a smaller cylinder' really that easy??
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Unread 28-01-2003, 22:14
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The force of a cylinder is simply A*P, where A is the cross-sectional area of the cylinder and P is the gauge pressure of the system. For example:

.75" bore: (.75/2)^2*pi*60= ~26 pounds
1" bore: (1/2)^2*pi*60= ~47 pounds
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