Quote:
Originally Posted by DonRotolo
Yes. That 15 in^3 would drop to zero if it remained at 120 PSI until the last actuation. In reality, it would drop about 4 PSI (1/30 * 120) each actuation, so after 15 actuations your storage pressure would be 60 PSI. You can do the math to see where you'll end up. Ryan's "double it" is reasonable.
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In the drop calculations, I'm assuming that the 4 PSI is dependent on the cylinder size? Or is that more of a rough constant?
- Sunny G.