|
First off, your team doesnt seem to have a concept of the physics of air pressure.
Putting pressure on both sides of a piston at the same time will just make for a slow extension of the cyclinder with a lot of stress.
The change in position is the relation of:
pi * r * PSI = output
r is your "bore", so for the 2" bore, 3.14 * 1" * 60psi = 188.4 lbs of output power.
Then inward pressure is slightly smaller because of where the rod attaches to the "bore cylinder" of the cylinder. So instead of an actual 2" surface diameter, it's (2" - rod diam). Thus more pressure is applied to extend the cylinder instead of retract it.
To stop the cylinder at 1/2 mast you need to control the exaust flow and the intake flow with another cylinnoid. I can't think of the wiring diagram right now sorry.
|