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Unread 10-02-2003, 07:22
Gobiner Gobiner is offline
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#0753 (High Desert Droids)
 
Join Date: Nov 2002
Location: Bend, Oregon
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Ok, team #753's fearless leader is a physics teacher, which has led to far more calculation and scrutiny towards everything than I think is ever due. But even though it's 4:12AM, I decided to figure out exactly what force is required for these winged king o' the hill robots. Assume 9 foot wings extending from center of gravity. Assume a high-traction track design with tracks at far corners of robot. Assume a robot can push with 100 lb of force. Said robot creates 10800 in-lb of torque on king robot (assuming center of gravity is pivot point). Corners of the track are 23.43 inches from center of gravity. To prevent the passage of attacking robot, they must have a force of friction of 461 lb exerted at the far corners of the robot. Now, to get that level of friction you'd need two suction cups that can exert 150 lb two (probably opposite) corners and have a 130 lb robot and have a coefficient of friction for both the suction cups and tracks of about 1.07. I don't think I did my math right, so am I missing something? King of the hill robots just seem silly to me if they have huge wings to prevent passage. Add to that the fact that your wings and mounts have to be able to withstand such a huge level of punishment.
Please, someone tell me I'm wrong.
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