Quote:
Originally Posted by Ether
Your approach looks correct, but your result for P(B(2000,1/3)<672) looks a bit off. What app did you use to compute the value .5929?
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Some web site, I can't remember. Trying another one gets me:
P(B(2000,1/3)<672) = .589957
P(B(100,.589957)>59) =
.4616
No?