Quote:
Originally Posted by bduddy
Some web site, I can't remember. Trying another one gets me:
P(B(2000,1/3)<672) = .589957
P(B(100,.589957)>59) = .4616
No?
|
Still no joy.
As in your first post, the second computation is correct, but the first is off a bit.
I suspect the web sites you are using implement algorithms which are not accurate for larger numbers.
But hey, you understood how to solve the problem. Reps to you!
PS:
I ran the numbers in Python, Octave, Scilab, and Maxima and they all agreed with each other out to ~12 sigfigs.
If anyone reading has access to Matlab and/or R, could you please post the result for:
p1 = binocdf(671,2000,1/3)