Quote:
Originally Posted by Jared
There will be more losses when a motor is at high current, high torque than when it is at it's free speed, but isn't this an ideal motor, so kt = 1/kv?
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Well, it depends on how you define an ideal motor. I am having trouble grasping what it would mean if a DC motor had no internal resistance and still followed the traditional equations with Kv and Kt and the rest--does this mean that it would always spin at its free speed for a given voltage, no matter what the torque or current going through it?