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Re: Motor moment of inertia
The equations on page 21 of the presentation don't appear to agree with the equations on page 20.
Using the 7.754E-05 kg*m^2 value for Jrotor for CIM from the spreadsheet to compute the equivalent mass at the vehicle I get ~22.8 pounds for a vehicle geared for 5 ft/sec (vehicle speed at CIM free speed of 5310 rpm).
For a 4-CIM drivetrain, that would be ~91 lbs. Doesn't seem right.
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