[GeeTwo]

For a CIM-based system, we usually figure this by looking at the 40A point on the performance curve, since we can maintain that speed for a time without tripping breakers. Then, look at the torque, multiply by your gear ratio, and divide by your moment arm (the radius of your pulley or half the pitch diameter of a sprocket). This will give you the theoretical lift force. You can probably expect a 10%-20% loss from there.

In your case, assuming a one-CIM, 16:1 gearbox driving a 15-tooth #35 sprocket (I have its pitch diameter of 1.8" memorized since we're using these this year in this application), that's 100 oz-in * 16 / .9in = 111 lb; plenty of lift, and very close to what 3946 is building. If your sprocket/pulley is larger, say 4" in diameter, it would only be about 50 lb, which (after losses) might not be enough to lift a stack of 6 totes.