Quote:
Originally Posted by Alan Anderson
It is a simple switch. It requires no power.
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This is correct. To add to what Alan said, this would make the switch be active low (i.e. the dio will read false when the switch closes), to make it active high you would connect it to 5v, but because the switch would cause a short circuit in that case you would have to put a resistor in series with it.
In short:
Ground - Switch - Input(on DIO) → active low
5v - switch - resistor (like 3.3k or bigger, but not too big) - input → active high
The first option is simpler, and it is easy to account for in software.